MCQ
If an iron $(III)$ complex with the formula $\left[\mathrm{Fe}\left(\mathrm{NH}_3\right)_{\mathrm{X}}(\mathrm{CN})_{\mathrm{Y}}\right]^{-}$has no electron in its $\mathrm{e}_{\mathrm{g}}$ orbital, then the value of $x+y$ is
  • A
    $5$
  • $6$
  • C
    $3$
  • D
    $4$

Answer

Correct option: B.
$6$
b
Complex is$\left[\mathrm{III}\left(\mathrm{NH}_3\right)_2(\mathrm{CN})_4\right]^{\Theta}$

$ x=2$

$y=4$

$\text { so } x+y=6$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free