MCQ
If angles $A , B$ and C are in A.P., then $\frac{ a + c }{ b }$ is equal to
  • A
    $2 \sin \frac{A- C }{2}$
  • $2 \cos \frac{A- C }{2}$
  • C
    $\cos \frac{ A - C }{2}$
  • D
    $\sin \frac{A-C}{2}$

Answer

Correct option: B.
$2 \cos \frac{A- C }{2}$
(B) $\frac{a+c}{b}=\frac{\sin A+\sin C}{\sin B}$
$=\frac{2 \sin \left(\frac{A+ C }{2}\right) \cos \left(\frac{ A - C }{2}\right)}{\sin B }$
$=\frac{2 \sin B}{\sin B } \cos \left(\frac{ A - C }{2}\right) \quad \ldots[\because 2 B= A + C ]$
$=2 \cos \left(\frac{A- C }{2}\right)$

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