MCQ
For all real values of  $x$ , increasing function  $f(x)$  is
  • A
    ${x^{ - 1}}$
  • B
    ${x^2}$
  • ${x^3}$
  • D
    ${x^4}$

Answer

Correct option: C.
${x^3}$
c
(c) Since $f(x) = {x^3} \Rightarrow f'(x) = 3{x^2},$

which is non-negative for all real values of $ x.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Consider a non-empty set consisting of children in a family and a relation R defined as aRb if a is brother of b. Then, R is:
  1. Symmetric but not transitive.
  2. Transitive but not symmetric.
  3. Neither symmetric nor transitive.
  4. Both symmetric and transitive.
The corner points of the feasible region determined by the system of linear constraints are (0, 10),(5, 5),(15, 15),(0, 20). Let z = px + qy where p, q > 0. Condition on p and q so that the maximum of z occurs at both the points (15, 15) and (0, 20) is __________:
  1. q = 2p
  2. p = 2p
  3. p = q
  4. q = 3p
The set of values of $‘a’$ which satisfy the equation

$\int\limits_0^2 {(t - {{\log }_2}a)\,dt} $ $= log_2$ $\left( {\frac{4}{{{a^2}}}} \right)$  is

The principal solution of $\cos ^{-1}\left(\cos \left(\frac{9 \pi}{4}\right)\right)$ is
$\frac{d}{{dy}}\left( {{{\sin }^{ - 1}}\left( {\frac{{3y}}{2} - \frac{{{y^3}}}{2}} \right)} \right) = $
Area lying between the parabola y2 = 4x and its latus rectum is:
  1. $\frac{1}{3}\text{ sq.}\text{units}$
  2. $\frac{2}{3}\text{ sq.}\text{units}$
  3. $\frac{5}{3}\text{ sq.}\text{units}$
  4. $\frac{8}{3}\text{ sq.}\text{units}$
The determinant $\left| {\,\begin{array}{*{20}{c}}{4 + {x^2}}&{ - 6}&{ - 2}\\{ - 6}&{9 + {x^2}}&3\\{ - 2}&3&{1 + {x^2}}\end{array}\,} \right|$ is not divisible by
If $y = {\tan ^{ - 1}}\left( {{{a\cos x - b\sin x} \over {b\cos x + a\sin x}}} \right)$ then ${{dy} \over {dx}} = $
$\int_{\pi /4}^{\pi /2} {\cos \theta \,{\rm{cose}}{{\rm{c}}^{\rm{2}}}\theta \,d\theta = } $
${d \over {dx}}\left[ {\log \sqrt {\sin \sqrt {{e^x}} } } \right]=$