MCQ
If $a=\sin ^{-1}(\sin (5))$ and $b=\cos ^{-1}(\cos (5))$, then $a^2+b^2$ is equal to
- A$4 \pi^2+25$
- ✓$8 \pi^2-40 \pi+50$
- C$4 \pi^2-20 \pi+50$
- D$25$
$\text { and } b=\cos ^{-1}(\cos 5)=2 \pi-5 $
$\therefore a^2+b^2=(5-2 \pi)^2+(2 \pi-5)^2 $
$=8 \pi^2-40 \pi+50$
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