If BD ⊥ AC and CE ⊥ AB, prove that ∆AEC ~ ∆ADB - Vidyadip

Question

If BD ⊥ AC and CE ⊥ AB, prove that ∆AEC ~ ∆ADB

✓

Answer

∠AEC = ∠ADB = 90°
∠A is common By AA – Similarity.
∴ ∆AEC ~ ∆ADB
Since the two triangles are similar.

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