MCQ
If between wavelength $\lambda$ and $\lambda+d \lambda, e_\lambda$ and $a_\lambda$ be the emissive and absorptive powers of a body and $E_\lambda$ be the emissive power of a perfectly black body, then according to Kirchoff's law, which is true
  • A
    $e_\lambda=a_\lambda=E_\lambda$
  • B
    $e_\lambda E_\lambda=a_\lambda$
  • $e_\lambda=a_\lambda E_\lambda$
  • D
    $e_\lambda a_\lambda E_\lambda=$ constant

Answer

Correct option: C.
$e_\lambda=a_\lambda E_\lambda$
According to Kirchoff's law, the ratio of emissive power to absorptive power is same for all bodies is equal to the emissive power of a perfectly black body i.e.,
$\left(\frac{e}{a}\right)_{\text {body }}=E_{\text {Blackbody }} \text { for a particular wave length } $
$\left(\frac{e_\lambda}{a_\lambda}\right)_{\text{body}}=\left(E_\lambda\right)_{\text {Blackbody }} \Rightarrow e_\lambda=a_\lambda E_\lambda$

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