MCQ
If $\frac{\big[\text{x} – 7\big]}{(\text{x} – 7)\geq 0}$ then:
  • A
    $\text{x}\in\big[7,\infty)$
  • $\text{x}\in(7,\infty)$
  • C
    $\text{x}\in(\infty, 7)$
  • D
    $\text{x}\in(-\infty, 7)$

Answer

Correct option: B.
$\text{x}\in(7,\infty)$
Given,
$\frac{|\text{x}-7|}{(\text{x}-7)}\geq0$
This is possible when $\text{x}-7\geq0,$ and $\text{x}-7\neq0.$
Here, $\text{x}\geq7$ but $\text{x}\neq7$
Therefore, $\text{x}> 7, \text{i}.\text{e}. \text{x}\in(7,\infty).$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The points (5, 2, 4), (6, -1, 2) and (8, -7, k) are collinear, if k is equal to:
For each positive integer $n$, let $y _{ n }=\frac{1}{ n }(( n +1)( n +2) \ldots( n + n ))^{\frac{1}{n}}$.

For $x \in R$, let $[x]$ be the greatest integer less than or equal to $x$. If $\lim _{n \rightarrow \infty} y_n=L$, then the value of $[ L ]$ is. . . . . . . .

If the line $x\, cos \theta + y\, sin \theta = 2$ is the equation of a transverse common tangent to the circles $x^2 + y^2 = 4$ and $x^2 + y^2 - 6 \sqrt{3} \,x - 6y + 20 = 0$, then the value of $\theta$ is :
If the eccentricity of the standard hyperbola passing, through the point $(4, 6)$ is $2$, then the equation of the tangent to the hyperbola at $(4, 6)$ is
How many permutations can be made by using all the letters of the word $'MATHEMAGICA'$ ?
If the focus of the parabola is $(3, -4)$ and the directrix is $y -4 = 0,$ then the equation of the parabola is :-
In a triangle ABC, a = 4, b = 3, $\angle\text{A}=60^{\circ}$ then c is a root of the equation:
The sum of the series $\frac{1}{1-3 \cdot 1^2+1^4}+$ $\frac{2}{1-3 \cdot 2^2+2^4}+\frac{3}{1-3 \cdot 3^2+3^4}+\ldots$. up to $10$ terms is
If $^{2n}{C_2}{:^n}{C_2} = 9:2$ and $^n{C_r} = 10$, then $r = $
The set of values of $x$ satisfying the equation,${2^{\tan \,\,\left( {x\,\, - \,\,{\textstyle{\pi  \over 4}}} \right)}}$ $- 2$${\left( {0.25} \right)^{\frac{{{{\sin }^2}\,\left( {x\,\, - \,\,{\textstyle{\pi  \over 4}}} \right)}}{{\cos \,\,2x}}}}$ $+ 1 = 0$, is :