MCQ
If $^{2n}{C_2}{:^n}{C_2} = 9:2$ and $^n{C_r} = 10$, then $r = $
- A$1$
- ✓$2$
- C$4$
- D$5$
$ \Rightarrow (2n)(2n - 1)2 = 9n(n - 1) \Rightarrow n = 5$
Now $^5{C_r} = 10 \Rightarrow r = 2$.
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