MCQ
If $c$ is any arbitrary constant, then $\int {{2^{{2^{{2^x}}}}}{2^{{2^x}}}{2^x}dx} $ is equal to
- A$\frac{{{2^{{2^x}}}}}{{{{(\ln 2)}^3}}} + c$
- ✓$\frac{{{2^{{2^{{2^x}}}}}}}{{{{(\ln 2)}^3}}} + c$
- C${2^{{2^{{2^x}}}}}{(\ln 2)^3} + c$
- DNone of these