MCQ
If $c^2=a^2+b^2$, then $4 s(s-a)(s-b)(s-c)=$
  • A
    $s^4$
  • B
    $b^2 c^2$
  • C
    $c^2 a^2$
  • $a^2 b^2$

Answer

Correct option: D.
$a^2 b^2$
(D) $\Delta$ is right angled, $\angle C =90^{\circ}$
$\therefore \quad \Delta=\frac{1}{2} ab \sin 90^{\circ}=\frac{1}{2} ab$
$\therefore \quad 4 \Delta^2-4\left(\frac{1}{2} a b\right)^2-a^2 b^2$

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