MCQ
If concentration of reactants is increased by $'x'$, then $K$ becomes
- Aln ($K/x$)
- B$K/x$
- C$K + x$
- ✓$K$
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Reason : In presence of $H_2SO_4$, $HNO_3$ acts as a base and produces $NO_2^+$ ions.
${C_6}{H_5} - H\mathop {\xrightarrow{{[X]}}}\limits_{AlC{l_3}} $ $\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{C}_{6}}{{H}_{5}}-C-C{{H}_{2}}-{{C}_{6}}{{H}_{5}} \\
\end{matrix}$
$[X]$ will be :