MCQ
If $\cos 3\theta = \alpha \cos \theta + \beta {\cos ^3}\theta ,$ then $(\alpha ,\beta ) = $
- A$(3,\,4)$
- B$(4,\,3)$
- ✓$( - 3,\,4)$
- D$(3,\, - 4)$
$= \alpha \cos \theta + \beta {\cos ^3}\theta $
But $\cos 3\theta = 4{\cos ^3}\theta - 3\cos \theta $
==> $(\alpha ,\beta ) = ( - 3,\,4)$.
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