MCQ
If $\cos A = \frac{{\sqrt 3 }}{2},$ then $\tan 3A = $
- A$0$
- B$1/2$
- C$1$
- ✓$\infty $
$\Rightarrow A = {30^o}$
==> $\tan 3A = \tan {90^o} = \infty $.
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