MCQ
If $\cos (\alpha - \beta ) = 1$ and $\cos (\alpha + \beta ) = \frac{1}{e}$, $ - \pi < \alpha ,\beta < \pi $, then total number of ordered pair of $(\alpha ,\beta )$ is
- A$0$
- B$1$
- C$2$
- ✓$4$
$\cos (\alpha - \beta ) = 1$
==> $\alpha - \beta = 0$
==> $\alpha = \beta $$\cos 2\alpha = \frac{1}{e}$
and $ - 2\pi < 2\alpha < 2\pi $
Hence, there will be four solutions.
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