- A$2$
- B$\sqrt 2 \,$
- C$3$
- ✓$\sqrt 3 \,$
Applying $C/D$
$ \Rightarrow = \frac{{1\,\, - \,\,\cos \,\alpha }}{{1\,\, + \,\,\cos \,\alpha }} = \frac{{3\,\left( {1\,\, - \,\,\cos \,\beta } \right)}}{{1\,\, + \,\,\cos \,\beta }}$
$\Rightarrow\, tan^2 \frac{\alpha}{2} = 3 tan^2 \frac{\beta}{2} \Rightarrow tan^2 \frac{\alpha}{2} \,cot^2 \frac{\beta}{2}= 3$
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$f(n)=\frac{\sum_{k=0}^n \sin \left(\frac{k+1}{n+2} \pi\right) \sin \left(\frac{k+2}{n+2} \pi\right)}{\sum_{k=0}^n \sin ^2\left(\frac{k+1}{n+2} \pi\right)}$
Assuming $\cos ^{-1} x$ takes values in $[0, \pi]$, which of the following options is/are correct ?
$(1)$ $\sin \left(7 \cos ^{-1} f(5)\right)=0$
$(2)$ $f(4)=\frac{\sqrt{3}}{2}$
$(3)$ $\lim _{n \rightarrow \infty} f(n)=\frac{1}{2}$
$(4)$ If $\alpha=\tan \left(\cos ^{-1} f(6)\right)$, then $\alpha^2+2 \alpha-1=0$