Question
If $(\cos x)^y=(\cos y)^x$, then $\frac{d y}{d x}$ is equal to:

Answer

Given, $(\cos x)^y=(\cos y)^x$
Taking \log on both sides, we get
$\log \left[(\cos x)^y\right]=\log \left[(\cos y)^x\right] \Rightarrow y \log (\cos x)=x \log (\cos y)$
Differentiate w.r.t. $x$, we get
$\frac{d y}{d x} \log (\cos x)+\frac{y}{\cos x}(-\sin x)=\log (\cos y)+\frac{x}{\cos y}(-\sin y) \cdot \frac{d y}{d x}$
$\Rightarrow \frac{d y}{d x}(\log (\cos x)+x \tan y)=\log (\cos y)+y \tan x$
$\Rightarrow \frac{d y}{d x}=\frac{y \tan x+\log (\cos y)}{x \tan y+\log (\cos x)}$

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