MCQ
If degree of ionisation is $0.01$ of decimolar solution of weak acid $HA$ then $pKa$ of acid is
  • $5$
  • B
    $7$
  • C
    $2$
  • D
    $3$

Answer

Correct option: A.
$5$
a
${K_a} = C{ \propto ^2} = 0.1 \times {(0.01)^2} = {10^{ - 5}}$

$pKa = 5$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free