MCQ
If $\frac{2 x}{3}-\frac{y}{2}+\frac{1}{6}=0$ and $\frac{x}{2}+\frac{2 y}{3}=3$ then
- ✓$x =2, y =3$
- B$x =-2, y =3$
- C$x =2, y =-3$
- D$x=-2, y=-3$
✓
Answer
Correct option: A.
$x =2, y =3$
$\frac{2x}{3}-\frac{y}{2}=-\frac{1}{6}$
$\Rightarrow \frac{4 x-3 y}{6}=-\frac{1}{6}$
$\Rightarrow 4 x-3 y=-1 \ldots \ldots(i)$
and $\frac{x}{2}+\frac{2 y}{3}=3$
$\Rightarrow \frac{3 x+4 y}{6}=3$
$\Rightarrow 3 x+4 y=18 \ldots \ldots(ii)$
On solving $eq. (i)$ and $(ii)$
$x=2, y=3
$
$\Rightarrow \frac{4 x-3 y}{6}=-\frac{1}{6}$
$\Rightarrow 4 x-3 y=-1 \ldots \ldots(i)$
and $\frac{x}{2}+\frac{2 y}{3}=3$
$\Rightarrow \frac{3 x+4 y}{6}=3$
$\Rightarrow 3 x+4 y=18 \ldots \ldots(ii)$
On solving $eq. (i)$ and $(ii)$
$x=2, y=3
$
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