MCQ
If $\frac{\big[\text{x} – 7\big]}{(\text{x} – 7)\geq 0}$ then:
  • A
    $\text{x}\in\big[7,\infty)$
  • B
    $\text{x}\in(7,\infty)$
  • C
    $\text{x}\in(\infty, 7)$
  • D
    $\text{x}\in(-\infty, 7)$

Answer

  1. $\text{x}\in(7,\infty)$

Solution:

 

Given,

$\frac{|\text{x}-7|}{(\text{x}-7)}\geq0$

This is possible when $\text{x}-7\geq0,$ and $\text{x}-7\neq0.$

Here, $\text{x}\geq7$ but $\text{x}\neq7$

Therefore, $\text{x}> 7, \text{i}.\text{e}. \text{x}\in(7,\infty).$

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