MCQ
If $\frac{|\text{x}-2|}{\text{x}-2}\geq0,$ then:
- A$\text{x}\in[2,\infty)$
- B$\text{x}\in(2,\infty)$
- C$\text{x}\in(-\infty,2)$
- D$\text{x}\in(-\infty,2]$
Solution:
$|\text{x}+2|\leq5$
$\Rightarrow-5\leq\text{x}+2\leq5$
$\Rightarrow-5-2\leq\text{x}+2-2\leq5-2$
$\Rightarrow-7\leq\text{x}\leq3$
$\Rightarrow\text{x}\in[-7,3]$
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$\sum(\text{x}_\text{i}-\bar{\text{x}})^2$
$\frac{\sum(\text{x}_\text{i}-\bar{\text{x}})^2}{\text{x}}$
$\sqrt{\frac{\sum(\text{x}_\text{i}-\bar{\text{x}})^2}{\text{n}}}$
$\frac{\sum\text{x}_\text{i}^2}{\text{n}}-(\bar{\text{x}})^{-2}$
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