If enthalpy of atomisation for Br_ 2(l) is x ; kJ / mol and bond … - Vidyadip

MCQ

If enthalpy of atomisation for $\mathrm{Br}_{2(l)}$ is $\mathrm{x}\; \mathrm{kJ} / \mathrm{mol}$ and bond enthalpy for $\mathrm{Br}_{2}$ is $y \;\mathrm{kJ} / \mathrm{mol}$, the relation between them

A
is $x = y$
B
is $x < y$
C
does not exist
✓
is $x > y$

✓

Answer

Correct option: D.

is $x > y$

d
Enthalpy of atomisation of $\mathrm{Br}_{2}(l)$

$\mathrm{Br}_{2}(l) \stackrel{\Delta \mathrm{H}_{\mathrm{vap}}}{\longrightarrow} \mathrm{Br}_{2}(\mathrm{g}) \stackrel{\Delta \mathrm{H}_{\mathrm{BE}}}{\longrightarrow} 2 \mathrm{Br}(\underline{\mathrm{g}})$

$\Delta \mathrm{H}_{\mathrm{atom}}=\Delta \mathrm{H}_{\mathrm{vap}}+\Delta \mathrm{H}_{\mathrm{BE}}$

$\mathrm{x}=\Delta \mathrm{H}_{\mathrm{vap}}+\mathrm{y}$

So, $x>y$

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