MCQ
If equilibrium constant of a reaction is $20.0,$ at equilibrium, rate constant of forward reaction is $10.0,$ then rate constant for backward reaction is
- ✓$0.5$
- B$2$
- C$10$
- D$200$
✓
Answer
Correct option: A.
$0.5$
a
${K_{eq}}\, = \,\frac{{{K_f}}}{{{K_b}}}\, \Rightarrow \,20\, = \,\frac{{10}}{{{K_b}}}$
${K_{eq}}\, = \,\frac{{{K_f}}}{{{K_b}}}\, \Rightarrow \,20\, = \,\frac{{10}}{{{K_b}}}$
${K_b} = 0.5$
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