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If for ${H_2}_{(g)} + \frac{1}{2}{S_{2(S)}}$ $\rightleftharpoons$ ${H_2}{S_{(g)}}$ and ${H_{2(g)}} + B{r_{2(g)}}$ $\rightleftharpoons$ $2HB{r_{(g)}}$The equilibrium constants are $K_1$ and $K_2$ respectively, the reaction$B{r_2}_{(g)} + {H_2}{S_{(g)}}$ $\rightleftharpoons$ $2HB{r_{(g)}} + \frac{1}{2}{S_{2(S)}}$ would have equilibrium constant

• A
  ${K_1}\; \times \;{K_2}$
• B
  ${K_1}/{K_2}$
• ✓
  ${K_2}/{K_1}$
• D
  $K_2^2/{K_1}$