MCQ
If function $f(x) = \left\{ \begin{array}{l}\frac{{{x^2} - 1}}{{x - 1}},\,\,{\rm{when}}\,\,x \ne 1\\\,\,\,\,\,\,\,\,\,\,\,\,k,\,{\rm{when}}\,\,x = 1\end{array} \right.$ is continuous at $x = 1$, then the value of $k$ will be
  • A
    $-1$
  • $2$
  • C
    $-3$
  • D
    $-2$

Answer

Correct option: B.
$2$
b
(b) $ \mathop {\lim }\limits_{x \to 1} f(x) = \mathop {\lim }\limits_{x \to 1} x + 1 = 2 = k.$

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