MCQ
If $f(x) = \left\{ \begin{array}{l}x\sin \frac{1}{x},\;\;\;\;\;x \ne 0\\\;\;\;\;\;\;0,\;\;\;\;\;x = 0\end{array} \right.$, then $\mathop {\lim }\limits_{x \to 0} f(x) = $
  • A
    $1$
  • $0$
  • C
    $-1$
  • D
    None of these

Answer

Correct option: B.
$0$
Here $f(0) = 0$
Since $ - 1 \le \sin \frac{1}{x} \le 1 $
$\Rightarrow - |x| \le x\sin \frac{1}{x} \le |x|$
We know that $\mathop {\lim }\limits_{x \to 0} |x|\, = 0$ and $\mathop {\lim }\limits_{x \to 0} |x|\, = 0$
In this way $\mathop {\lim }\limits_{x \to 0} f(x) = 0.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free