MCQ
If $f(x) = \sin x - {x \over 2}$ is increasing function, then
- A$0 < x < {\pi \over 3}$
- B$ - {\pi \over 3} < x < 0$
- ✓$ - {\pi \over 3} < x < {\pi \over 3}$
- D$x = {\pi \over 2}$
$f'(x) > 0$ for increasing function
Obviously it is increasing for $ - \frac{\pi }{3} < x < \frac{\pi }{3}$.
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has infinitely many solutions, then $a - b$ is equal to
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$\text{None os these}.$