MCQ
If $f(x)=|\cos x|$, then $f\left(\frac{3 \pi}{4}\right)$ is
  • A
    1
  • B
    -1
  • C
    $\frac{-1}{\sqrt{2}}$
  • D
    $\frac{1}{\sqrt{2}}$

Answer

$f(x)=|\cos x|$
At$\frac{\pi}{2}$ < x < $\pi, \cos x<0$$\therefore|\cos x|=-\cos x \Rightarrow f(x)=-\cos x$
$\begin{array}{l}\therefore \quad f\left(\frac{3 \pi}{4}\right)=-\cos \left(\frac{3 \pi}{4}\right)=-\cos \left(\pi-\frac{\pi}{4}\right) \\\quad=\cos \frac{\pi}{4}=\frac{1}{\sqrt{2}} \quad[\because \cos (\pi-\theta)=-\cos \theta]\end{array}$

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