MCQ
If $HN{O_3}$ changes into ${N_2}O$, the oxidation number is changed by
- A$+2$
- B$-1$
- C$0$
- ✓$+4$
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Statement $I$ :- Methyl orange is a weak acid.
Statement $II$ :- The benzenoid form of methyl orange is more intense/deeply coloured than the quinonoid form.
In the light of the above statement, choose the most appropriate answer from the options given below :-
$(I) \,C{H_3}CH = C{H_2} + HBr\xrightarrow{{peroxide}}$
$(II)\, C{H_3}CH = C{H_2} + HBr\xrightarrow{{CC{l_4}}}$
$(III)\, C{H_3}C{H_2}C{H_3} + B{r_2}\xrightarrow{{hv}}$
$(IV)\,C{H_3}CH = C{H_2} + B{r_2}\xrightarrow{{CC{l_4}}}$