MCQ
If $(i)$ $C + {O_2} \to C{O_2}$, $(ii)$ $C + 1/2{O_2} \to CO$, $(iii)$ $CO + 1/2{O_2} \to C{O_2}$, the heats of reaction are $Q,\, - 12,\, - 10$ respectively. Then $Q = $
- A$-2$
- B$2$
- ✓$-22$
- D$-16$
✓
Answer
Correct option: C.
$-22$
(c)$C + {O_2} \to C{O_2}$; $\Delta H = q$
$C + 1/2{O_2} \to CO$; $\Delta H = - 12$ …..$(i)$
$CO + 1/2{O_2} \to C{O_2}$; $\Delta H = - 10$ …..$(ii)$
adding equation $(i)$ and $(ii)$ we can get
$\Delta H = - 12 + ( - 10) = - 22$
$C + 1/2{O_2} \to CO$; $\Delta H = - 12$ …..$(i)$
$CO + 1/2{O_2} \to C{O_2}$; $\Delta H = - 10$ …..$(ii)$
adding equation $(i)$ and $(ii)$ we can get
$\Delta H = - 12 + ( - 10) = - 22$
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