If in a binomial distribution $\text{n}=4,\text{P(X}=0)=\frac{16}{81},$ then $\text{P(X}=4)$ equals:
  • A$\frac{1}{16}$
  • B$\frac{1}{81}$
  • C$\frac{1}{27}$
  • D$\frac{1}{8}$
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