If A and B are such that $\text{P}(\text{A}\cup\text{B})=\frac{5}{9}$ and $\text{P}(\overline{\text{A}}\cup\overline{\text{B}})=\frac{2}{3},$ then $\text{P}(\overline{\text{A}})+\text{P}(\overline{\text{B}})=$
  • A$\frac{9}{10}$
  • B$\frac{10}{9}$
  • C$\frac{8}{9}$
  • D$\frac{9}{8}$
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