MCQ
If intensity of each wave in the observed interference pattern in Young's double slit experiment is $I_0$. then for some point $P$ where the phase difference is $\phi $ , intensity $I$ will be
  • A
    $I = I_0\,\,cos\,\phi $
  • B
    $I = I_0\,\,cos^2\,\phi $
  • C
    $I = I_0\,\,(1+cos\,\phi )$
  • $I = 2I_0\,\,(1+cos\,\phi )$

Answer

Correct option: D.
$I = 2I_0\,\,(1+cos\,\phi )$
d
$\mathrm{I}=\mathrm{I}_{1}+\mathrm{I}_{2}+2 \sqrt{1_{1} \mathrm{I}_{2}} \cos \phi$

$\mathrm{I}_{\mathrm{R}}=\mathrm{I}_{0}+\mathrm{I}_{0}+2 \sqrt{I_{0} I_{0}} \cos \phi$

$\boxed{{{\text{I}}_{\text{R}}} = 2{{\text{I}}_0}(1 + \cos \phi )}$

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