Given,
$\int_\text{s}\text{E.dS}=0$
It means the algebraic sum of number of flux lines entering the surface and number of flux lines leaving the surface.
Now, from Gauss' law,
$\int_\text{S}\text{E.dS}=\frac{\text{q}}{\in_0}$
Where q is charge enclosed by the surface.
Now,
$\int_\text{s}\text{E.dS}=0$
q = 0 i.e., net charge enclosed by the surface must be zero.
Hence, all other charges must necessarily be outside the surface.
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In order to increase the angular magnification of a simple microscope, one should increase:
Mixed 
and 
ions (mass of 
and that of 
beam passes a region of constant perpendicular magnetic field. If kinetic energy of all the ions is same then
|
(a) |
|
(b) |
|
(c) All the ions will be deflected equally |
|
(d) No ions will be deflected |
A ray of light is incident on the surface of separation of a medium at an angle 45° and is refracted in the medium at an angle 30°. What will be the velocity of light in the medium
|
(a) 1.98 |
(b) 2.12 |
(c) 3.18 |
(d) 3.33 |
