MCQ
If $\left[\begin{array}{cc}x & 0 \\ -3 & 1\end{array}\right]\left[\begin{array}{ll}1 & 1 \\ 0 & y\end{array}\right]=\left[\begin{array}{rr}2 & 2 \\ -3 & -2\end{array}\right]$ then value of $x$ and $y$ is:
  • A
    $x=1, y=2$
  • B
    $x=-1, y=2$
  • $x=2, y=1$
  • D
    $x=2, y=-1$

Answer

Correct option: C.
$x=2, y=1$
(c) $x=2, y=1$
Explanation:
$\begin{array}{l}\text { Here, }\left[\begin{array}{cc}x & 0 \\ -3 & 1\end{array}\right]\left[\begin{array}{ll}1 & 1 \\ 0 & y\end{array}\right]=\left[\begin{array}{rr}2 & 2 \\ -3 & -2\end{array}\right] \\ \Rightarrow\left[\begin{array}{cc}x & x \\ -3 & -3+y\end{array}\right]=\left[\begin{array}{cc}2 & 2 \\ -3 & -2\end{array}\right] \\ \Rightarrow x=2 \text { and }-3+y=-2 \\ \Rightarrow x=2 \text { and } y=1\end{array}$

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