MCQ
If $\left| {\begin{array}{*{20}{c}}{{x_1}}&{{y_1}}&1\\{{x_2}}&{{y_2}}&1\\{{x_3}}&{{y_3}}&1\end{array}} \right| = \left| {\begin{array}{*{20}{c}}{{a_1}}&{{b_1}}&1\\{{a_2}}&{{b_2}}&1\\{{a_3}}&{{b_3}}&1\end{array}} \right|$, then the two triangle with vertices $({x_1},{y_1}),\,({x_2},{y_2}),\,$ $({x_3},{y_3})$ and $({a_1},{b_1}),\,$ $\,({a_2},{b_2}),$ $({a_3},{b_3})$ must be
  • A
    Similar
  •  None of these
  • C
    Never congruent
  • D
    Congruent

Answer

Correct option: B.
 None of these
b
(b) By the given condition, we mean that the areas of both triangles are same. But it does not mean that the triangles are congruent.

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