Question
If $\mathrm{A}=\left[\begin{array}{cc}1 & 2 i \\ -3 & 2\end{array}\right]$ and $\mathrm{B}=\left[\begin{array}{cc}2 i & 1 \\ 2 & -3\end{array}\right]$ where $i=\sqrt{-1}$, find $\mathrm{A}+\mathrm{B}$ and $\mathrm{A}-\mathrm{B}$. Show that $\mathrm{A}$

+ B is singular. Is A – B singular? Justify your answer.

Answer

$\begin{aligned} A+B & =\left[\begin{array}{cc}i & 2 i \\ -3 & 2\end{array}\right]+\left[\begin{array}{cc}2 i & i \\ 2 & -3\end{array}\right] \\ & =\left[\begin{array}{cc}i+2 i & 2 i+i \\ -3+2 & 2-3\end{array}\right]=\left[\begin{array}{cc}3 i & 3 i \\ -1 & -1\end{array}\right]\end{aligned}$

$\therefore \quad|A+B|=\left|\begin{array}{cc}3 \mathrm{i} & 3 \mathrm{i} \\ -1 & -1\end{array}\right|$

$=3 \mathrm{i}(-1)-(-1) 3 \mathrm{i}=0$

$\therefore \quad \mathrm{A}+\mathrm{B}$ is a singular matrix.

$\begin{aligned} A-B & =\left[\begin{array}{cc}i & 2 i \\ -3 & 2\end{array}\right]-\left[\begin{array}{cc}2 i & i \\ 2 & -3\end{array}\right] \\ & =\left[\begin{array}{cc}i-2 i & 2 i-i \\ -3-2 & 2+3\end{array}\right]=\left[\begin{array}{cc}-i & i \\ -5 & 5\end{array}\right]\end{aligned}$

$\therefore \quad|\mathrm{A}-\mathrm{B}|=\left|\begin{array}{ll}-\mathrm{i} & \mathrm{i} \\ -5 & 5\end{array}\right|=(-\mathrm{i}) 5-(-5) \mathrm{i}=0$

$\therefore \quad \mathrm{A}-\mathrm{B}$ is also a singular matrix.

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