+ B is singular. Is A – B singular? Justify your answer.
+ B is singular. Is A – B singular? Justify your answer.
$\therefore \quad|A+B|=\left|\begin{array}{cc}3 \mathrm{i} & 3 \mathrm{i} \\ -1 & -1\end{array}\right|$
$=3 \mathrm{i}(-1)-(-1) 3 \mathrm{i}=0$
$\therefore \quad \mathrm{A}+\mathrm{B}$ is a singular matrix.
$\begin{aligned} A-B & =\left[\begin{array}{cc}i & 2 i \\ -3 & 2\end{array}\right]-\left[\begin{array}{cc}2 i & i \\ 2 & -3\end{array}\right] \\ & =\left[\begin{array}{cc}i-2 i & 2 i-i \\ -3-2 & 2+3\end{array}\right]=\left[\begin{array}{cc}-i & i \\ -5 & 5\end{array}\right]\end{aligned}$
$\therefore \quad|\mathrm{A}-\mathrm{B}|=\left|\begin{array}{ll}-\mathrm{i} & \mathrm{i} \\ -5 & 5\end{array}\right|=(-\mathrm{i}) 5-(-5) \mathrm{i}=0$
$\therefore \quad \mathrm{A}-\mathrm{B}$ is also a singular matrix.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\left[\begin{array}{rr}4 & -2 \\ 3 & -5\end{array}\right]$