Question
If $\mathrm{x}=2 \sqrt{ } 3+2 \sqrt{2}$, find $:\left(x+\frac{1}{x}\right)^2$
✓
Answer
$ \left(x+\frac{1}{x}\right)^2=\left[5 \sqrt{3}+3 \frac{\sqrt{2}}{2}\right]^2$
$ =\frac{75+18+30 \sqrt{6}}{4}$
$ =\frac{93+30 \sqrt{6}}{4}$
$ =\frac{75+18+30 \sqrt{6}}{4}$
$ =\frac{93+30 \sqrt{6}}{4}$
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