- ✓$4$
- B$2$
- C$6$
- D$8$
$\mu=\frac{1}{2}$
$\frac{V_{m}}{V_{c}}=\frac{1}{2}$
Solve the above equation for $V_{ c }$
$V_{ c }=2 V_{ m }$
$=2 \times 2$
$=4$
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$(A)$ If $f$ is increased keeping $I$ and work function constant then maximum kinetic energy of photoelectron increases
$(B)$ If distance between cathode and anode is increased stopping potential increases
$(C)$ If $I$ is increased keeping $f$ and work function constant then stopping potential remains same and saturation current increases
$(D)$ Work function is decreased keeping $f$ and $I$ constant then stopping potential increases

$STATEMENT-2$ The molecules of a gas collide with each other and the velocities of the molecules change due to the collision.