MCQ
If monosaccharide contains an aldehyde group, it is known as
- AEpimer
- BOsones
- COsazone
- ✓Aldose
✓
Answer
Correct option: D.
Aldose
d
An aldose is a monosaccharide (a simple sugar) with a carbon backbone chain with a carbonyl group on the endmost carbon atom, making it an aldehyde, and hydroxyl groups connected to all the other carbon atoms.
An aldose is a monosaccharide (a simple sugar) with a carbon backbone chain with a carbonyl group on the endmost carbon atom, making it an aldehyde, and hydroxyl groups connected to all the other carbon atoms.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Nitrogen reacts with a metal $M$ to produce a compound $X.$ This compound $X,$ when dissolved in water forms pungent gas $Y$ which can be identified easily by the formation of white fumes in the presence of $\text{HCl}.$ Identify the compound $X.$
→Acetophenone is prepared by the reaction of which of the following in the presence of $AlC{l_3}$ catalyst
→Amongst the following alcohols which would react fastest with conc. $HCl$ and $ZnCl_2$ ?
→If equivalent conductance of $1\,M$ benzoic acid is $12.8\, ohm^{-1}\, cm^2\, eq^{-1}$ and if the equivalent conductances of benzoate ion and $H^+$ ion at infinite dilution are $42$ and $288.42\, ohm^{-1}\, cm^2\, eq^{-1}$ respectively, then its degree of dissociation is ............ $\%$
→The spin only magnetic moments (in $BM$) for free $\mathrm{Ti}^{3+}, \mathrm{V}^{2+}$ and $\mathrm{Sc}^{3+}$ ions respectively are (At.No. $Sc: 21; Ti : 22; V : 23)$
→Which of the following is a source of instant energy?
Resistance of $0.2\, M$ solution of an electrolyte is $50 \Omega .$The specific conductance of the solution is $1.4\, S\, m^{-1}.$ The resistance of $0.5\, M$ solution of the same electrolyte is $280\, \Omega .$ The molar conductivity of $0.5\, M$ solution of the electrolyte in $S\, m^2\, mol^{-1}$ is :
→Consider the hydrated ions of $Ti^{2+}, V^{2+}, Ti^{3+}$ and $Sc^{3+}$. The correct order of their spin-only magnetic moments is
→Which of the following statement is correct
$[ P ]$ on treatment with $Br _{2} / FeBr _{3}$ in $CCl _{4}$produced a single isomer $C _{8} H _{7} O _{2}$ $Br$ while heating $[P]$ with sodalime gave toluene.
→The compound $[P]$ is :