If $n$ represents the actual number of deflections in a converted galvanometer of resistance $G$ and shunt resistance $S$. Then the total current I when its figure of merit is $K$ will be
JEE MAIN 2022, Medium
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Figure of merit $\frac{ I _{ g }}{\theta}= K$
$I _{ g }= Kn$
$I =\frac{ I _{ g }}{ s }( G + S )$
$I =\frac{ nK }{ S }( G + S )$
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