MCQ
If $^n{C_{12}} = {\,^n}{C_6}$, then $^n{C_2} = $
- A$72$
- ✓$153$
- C$306$
- D$2556$
$12 + 6 = n \Rightarrow n = 18$
$^{18}{C_2} = \frac{{18 \times 17}}{2} = 9 \times 17 = 153$.
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Statement $1$ : $z$ is a real number
Statement $2$ : Principal argument of $z$ is $\frac{\pi }{3}$