MCQ
If $|a|\, = 3,\,\,|b|\, = 4$ then a value of $\lambda$ for which $a + \lambda b$ is perpendicular to $a - \lambda b$ is
  • A
    $\frac{9}{16}$
  • $\frac{3}{4}$
  • C
    $\frac{3}{2}$
  • D
    $\frac{4}{3}$

Answer

Correct option: B.
$\frac{3}{4}$
b
(b) Since $a + \lambda b$ is perpendicular to $a - \lambda b$, then their product will be zero.

So, $(a + \lambda b).(a - \lambda b) = 0$ ==> $|a{|^2} - {\lambda ^2}|b{|^2} = 0$

or ${\lambda ^2} = \frac{{|a{|^2}}}{{|b{|^2}}} \Rightarrow {\lambda ^2} = \frac{9}{{16}}$ or $\lambda = \pm \frac{3}{4}$, 

$[\because \,|a| = 3,|b| = 4]$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The adjoint of the matrix $\left[\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right]$ is
The area bounded by curve $y = x^2- 1$ and tangents to it at $(2, 3)$ and $y -$ axis is:
Let $a = 2i - j + k,\,\,b = i + 2j - k$ and $c = i + j - 2k$ be three vectors. A vector in the plane of $ b $ and $c $ whose projection on $a$ is of magnitude $\sqrt {2/3} $ is
For the function $f(x) = {x^2} - 6x + 8,2 \le x \le 4$, the value of $x$  for which $f'(x)$ vanishes, is
If $u = \sqrt {{a^2}{{\cos }^2}\theta + {b^2}{{\sin }^2}\theta } + \sqrt {{a^2}{{\sin }^2}\theta + {b^2}{{\cos }^2}\theta } $, then difference between the maximum and minimum values of ${u^2}$ is given by
$\left| {\,\begin{array}{*{20}{c}}1&5&\pi \\{{{\log }_e}e}&5&{\sqrt 5 }\\{{{\log }_{10}}10}&5&e\end{array}\,} \right| = $
Let $f(\alpha ) = \int\limits_0^\alpha  {{x^2}{{\left( {1 - \frac{x}{\alpha }} \right)}^\alpha }} dx$ (where $\alpha > 0)$, then $\sum\limits_{\alpha  = 1}^5 {\frac{{f(\alpha )}}{{{\alpha ^3}}}} $  is equal to-
Let $\vec{a}=\hat{i}+2 \hat{j}+3 \hat{k}, \quad \vec{b}=2 \hat{i}+3 \hat{j}-5 \hat{k} \quad$ and $\overrightarrow{\mathrm{c}}=3 \hat{\mathrm{i}}-\hat{\mathrm{j}}+\lambda \hat{\mathrm{k}}$ be three vectors. Let $\overrightarrow{\mathrm{r}}$ be a unit vector along $\vec{b}+\vec{c}$. If $\vec{r} . \vec{a}=3$, then $3 \lambda$ is equal to :
The direction ratios of two lines $AB, AC$ are $1, -1, -1$ and $2, -1, 1.$ The direction ratios of the normal to the plane $\text{ABC}$ are:
The maximum value of the function $f(x)=2 x^3-15 x^2+36 x-48$ on the set $A=\left\{x \mid x^2+20 \leq 9 x\right\}$ is