- A$90$
- B$120$
- ✓$0$
- D$60$
$\overrightarrow R = \overrightarrow A + \overrightarrow B $
$|\overrightarrow R |\, = \,|\overrightarrow A + \overrightarrow B |\, = \sqrt {{A^2} + {B^2} + 2AB\cos \theta } $
If $\theta = 0^\circ $ then $|\overrightarrow R |\, = A + B$$ = \,|\overrightarrow A | + |\overrightarrow B |$
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[Figure shows position of reference $'O'$ when jaws of screw gauge are closed]
Given pitch $=0.1 \,{cm}$.


$1.$ The ratio of $x_1 / x_2$ is
$(A)$ $2$ $(B)$ $\frac{1}{2}$ $(C)$ $\sqrt{2}$ $(D)$ $\frac{1}{\sqrt{2}}$
$2.$ When disc $\mathrm{B}$ is brought in contact with disc $\mathrm{A}$, they acquire a common angular velocity in time $\mathrm{t}$. The average frictional torque on one disc by the other during this period is
$(A)$ $\frac{2 \mathrm{I} \omega}{3 \mathrm{t}}$ $(B)$ $\frac{9 \mathrm{I} \omega}{2 \mathrm{t}}$ $(C)$ $\frac{9 \mathrm{I} \omega}{4 \mathrm{t}}$ $(D)$ $\frac{3 \mathrm{I} \omega}{2 \mathrm{t}}$
$3.$ The loss of kinetic energy during the above process is
$(A)$ $\frac{\mathrm{I} \omega^2}{2}$ $(B)$ $\frac{\mathrm{I} \omega^2}{3}$ $(C)$ $\frac{\mathrm{I} \omega^2}{4}$ $(D)$ $\frac{\mathrm{I} \omega^2}{6}$
Give the answer question $1,2$ and $3.$