MCQ
If $|\vec{a}|=2,|\vec{b}|=5$ and $|\vec{a} \times \vec{b}|=8$, then $|\vec{a} \cdot \vec{b}|$ is equal to :
- A$5$
- B$4$
- ✓$6$
- D$3$
$|\vec{a} \times \vec{b}|=|\vec{a}||\vec{b}| \sin \theta=\pm 8$
$\sin \theta=\pm \frac{4}{5}$
$\therefore \vec{a} \cdot \vec{b}=|\vec{a}| \vec{b} \mid \cos \theta$
$=10 \cdot\left(\pm \frac{3}{5}\right)=\pm 6$
$|\vec{a} \cdot \vec{b}|=6$
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