Question
If $|\vec{\text{a}}|=\sqrt{3},|\vec{\text{b}}|=2\text{ and }\vec{\text{a}}\cdot\vec{\text{b}}=3$find the angle between $\vec{\text{a}}$and $\vec{\text{b}}$.

Answer

$\theta=\cos^{-1}\Bigg(\frac{\sqrt{3}} {2}\Bigg)=\frac{\pi}{6}.$

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