Question
If $|\vec{\text{a}}|=10,\big|\vec{\text{b}}\big|=2$ and $\big|\vec{\text{a}}\times\vec{\text{b}}\big|=16,$ find $\vec{\text{a}}.\vec{\text{b}}.$
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$\sqrt{x}+\sqrt{y}=\sqrt{a}$
| $X=x$ | $0$ | $1$ | $2$ | $3$ | $4$ |
| $P(X=x)$ | $0.1$ | $K$ | $2K$ | $2K$ | $K$ |