MCQ
If $|\text{x} – 1| > 5$ then:
- A$\text{x}\in(-4,6)$
- B$\text{x}\in\big[-4,6\big]$
- C$\text{x}\in(-\infty,-4)\cup(6,\infty)$
- D$\text{x}\in\big[-\infty,-4)\cup\big[6,\infty)$
Solution:
$|\text{x} – 1| > 5$
$\text{x} – 1 < - 5 $ and $\text{x} – 1 > - 5 $
$\text{x} < -4 $ and $\text{x} > 6 $
$\therefore\text{x}\in(-\infty,-4)\cup(6,\infty)$
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