MCQ
If $|\text{x} + 3|\geq10,$ then:
- A$\text{x}\in(-13,7\big)$
- B$\text{x}\in(-13,7\big]$
- C$\text{x}\in(-\infty -13\big]\cup \big[7,\infty)$
- D$\text{x}\in\big[-\infty -13\big]\cup \big[7,\infty)$
Solution:
$|\text{x} + 3|\geq10$
$\Rightarrow\text{x} + 3\leq-10$ or $\text{x}+3\geq10$
$\Rightarrow\text{x}\leq -13 $ or $\text{x}\geq7$
$\Rightarrow\text{x}\in\big[-\infty -13\big]\cup \big[7,\infty)$
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