MCQ
If |x−1| x - 1 > 5, then:
  • A
    $\text{x}\in(-4,6)$
  • B
    $\text{x}\in[-4,6]$
  • C
    $\text{x}\in(-\infty,-4)\cup(6,\infty)$
  • D
    $\text{x}\in(-\infty,-4)\cup[6,\infty)$

Answer

  1. $\text{x}\in(-\infty,-4)\cup(6,\infty)$

Solution:

|x−1| > 5

⇒ x − 1 > 5 or x − 1 < −5

⇒ x > 5 + 1 or x < −5 + 1

⇒ x > 6 or x < −4

$\Rightarrow\text{x}\in(-\infty,-4)\cup(6,\infty)$

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