MCQ
If |x−1| x - 1 > 5, then:
- A$\text{x}\in(-4,6)$
- B$\text{x}\in[-4,6]$
- C$\text{x}\in(-\infty,-4)\cup(6,\infty)$
- D$\text{x}\in(-\infty,-4)\cup[6,\infty)$
Solution:
|x−1| > 5
⇒ x − 1 > 5 or x − 1 < −5
⇒ x > 5 + 1 or x < −5 + 1
⇒ x > 6 or x < −4
$\Rightarrow\text{x}\in(-\infty,-4)\cup(6,\infty)$
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