MCQ
If $P(E) = 0.05,$ what will be the probability of 'not $E\ '$?
- A$0.55$
- B$0.59$
- ✓$0.95$
- D$0.095$
✓
Answer
Correct option: C.
$0.95$
We know that
$P(E)+P(\text { not } E)=1$
$\therefore P(\text { not } E) =1-P(E)$
$ =1-0.05$
$ =0.95$
$P(E)+P(\text { not } E)=1$
$\therefore P(\text { not } E) =1-P(E)$
$ =1-0.05$
$ =0.95$
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